F(x) = 16x4 – 81 = 0 select all of the zeroes of the function.
3/2
-3/2
3/2i
-3/2i

Here we want to find all the zeros of the function f(x) = 16*x^4 - 81.

The zeros are:

First, for a given function f(x), we define the zeros as the values of x such that:

f(x) = 0.

Then we must solve:

f(x) = 16*x^4 - 81 = 0

Solving this for x leads to:

16*x^4 = 81

x^4 =  81/16

x^2 = ±√(81/16) = 9/4

x = ±√±(9/4) = ±3/2 and ±(3/2)*i

So there are 4 zeros, and these are:

Where the two complex zeros come from evaluating the second square root on -9/4.

If you want to learn more, you can read.

link

12

step-by-step explanation:

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2