Two women start at the same point. they walk in opposite directions for 3 meters, then turn right and walk another 4 meters. how far apart are they?

The total distance between the two women would simply be the sum of the hypotenuse formed by the triangular path they created.

For each women:

c^2  = a^2 + b^2

c^2 = 3^2 + 4^2

c^2 = 9 + 16

c^2 = 25

c = 5 m

Therefore the distance between the two is:

distance between the two women = 2 * c

distance between the two women = 10 m

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1