The depreciating value of a semi-truck can be modeled by y = ao(0.83)x, where y is the remaining value of the semi, x is the time in years, and it depreciates at 17% per year.
an exponential function comes down from the positive infinity and passes through the points zero comma seventy thousand. the graph is approaching the x-axis. what is the value of the truck initially, ao, and how would the graph change if the initial value was only $50,000?

$70,000, and the graph would have a y-intercept at 50,000
$60,000, and the graph would have a y-intercept at 70,000
$70,000, and the graph would fall at a slower rate to the right
$70,000, and the graph would fall at a faster rate to the right

Option A is correct.

Step-by-step explanation:

We are given that, the model for the depreciating value of a semi-truck is,

1. It is required to find the value of the truck initially i.e. when x= 0.

So, substituting x= 0, we have,

i.e.

i.e.

Since, the graph passes through the point (0,70,000).

Thus, we get,

Hence, the initial value is 70,000.

2. It is required to find the value of the truck initially i.e. when x= 50,000

That is, when x= 0, the value of y= 50,000.

Graphically, it means that the graph would cut y-axis at the point (0,50,000).

Thus, the y-intercept would be at 50,000.

Change in the initial value will not have any affect on the rate of the graph.

So, from the above, we get,

Option A is correct.

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)