The vertex of a parabola is (-1.5, -12.5), and its y-intercept is (0, -8).
the x-intercepts of the parabola are

The x-intercept are x=-4,1.                    

Step-by-step explanation:

Given : The vertex of a parabola is (-1.5, -12.5), and its y-intercept is (0, -8).

To find : The x-intercepts of the parabola are ?

Solution :

The general form of the parabola equation is  

......(1)

where, a is the initial value and (h,k) are vertex of the parabola.

We have given the vertex (h,k)=(-1.5, -12.5)

Substitute in equation (1),

......(2)

Now, The y-intercept is (0,-8)

Substitute in equation (2),

Put back in equation (2),

To find the x-intercept put y=0 in above equation,

Solve by middle term split,

Therefore, The x-intercept are x=-4,1.

x^5/3y^1/3 the correct answer

hope it

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: