What is the initial value of y=-2x-5

This problem can be solved easily. The equation states that y is a function of x. Since this is the case, then we can get the initial value of the function when x = 0. Therefore by substitution:

y = - 2 x -5

y = - 2 (0) – 5

y = -5                     (ANSWER)

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0