Aramis showed the division of 6p2 + 9p + 3 by 3p.
a + 3 + b
what are the values of a and b?
a) a = 2p and b = p
b) a = 3p and b = p
c) a = 2/p and b = 1/p
d) a = 2p and b = 1/p

D) A = 2p and B = 1/p

Step-by-step explanation:

To divide this, we first see how many times 3p will go into 6p².  It will go in 2p times; this goes up top of the problem.

Multiplying back through, we have

2p(3p) = 6p².  Subtracting this from the first term under the box, we have

6p²-6p² = 0.  This cancels.  Bring down the next term, 9p.

See how many times 3p goes into 9p it goes in 3 times.  This goes up top, beside the 2p.  We separate them with a +, since the 3 is positive.

Multiplying back through, we have 3(3p) = 9p.  Subtract this from the line above; 9p-9p = 0.  Bring down the last term, 3.  Since this is not 0, this is the remainder.  This gives us

2p + 3 R 3; writing this as a rational expression, we have

2p + 3 + 3/3p

The remainder term, 3/3p, will simplify to 1/1p or 1/p; this gives us

2p + 3 + 1/p

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step-by-step explanation: