How much water should be added to 14 ml of 15% alcohol solution to reduce the concentration to 7%?

So hmmm we'll start off by using the decimal format for the percentage, thus 15% is just 15/100 or 0.15 and 7% is just 7/100 or 0.07 and so on

notice, the concentration of alcohol in the 15% is, well, 0.15 :), so for a quantity of whatever, it'd be 0.15whatever

anyway, for water... water has no alcohol whatsoever, so the concentration is 0%, or 0/100 which is 0.00 or a flat 0



we know that we'll be adding "x" water with the 14mL to get "y", thus 14+x = y

and the concentrated quantities will also add up to -> 14(0.15) = 2.1, thus
2.1 + 0x = 0.07y



solve for "x".

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*