Find the values of x and y for which the lines are parallel.
x = 46, y = 72
x = 68, y = 72
x = 72, y = 68
x = 68, y = 74

The   " x = 68, y = 72 " .

Explanation:

46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:

 40 + x + y - 40 = 180 - 40 ;

 to get:

x + y = 140 ;

Now:

65 = (x - 3) ;

↔  x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:
 
           x = 68 .

Now:

Since:  "x + y = 140" ;

Let us plug in our known value, "68" ;  for "x" ;

to solve for "y" ;

   x + y = 140 ;
 
  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;

   y + 68 - 68 = 140 = 68 ;

                  y = 72 .

So,  solve for "x" and "y".

x = 68, y = 72 .

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