![\bf \sqrt[3]{27a^3b^7}\quad \begin{cases} 27=3\cdot 3\cdot 3\\ \qquad 3^3\\ b^7=b^{3+3+1}\\ \qquad b^3b^3b^1\\ \qquad (b^2)^3b^1 \end{cases}\implies \sqrt[3]{3^3a^3(b^2)^3b^1} \\\\\\ 3ab^2\sqrt[3]{b^1}\implies 3ab^2\sqrt[3]{b}](/tpl/images/0350/3771/ff961.png)
What is the simplest form of ^3 square root 27a^3b^7
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