Mathematics

Mathematics, 19.10.2019 14:10, samiiegarciia

Abcd is a parallelogram. if m d=85 then what is m c

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Mathematics, 22.06.2019 19:40, Priskittles

Parallelogram abcd has vertices: a(-3,1), b(3, 3), c(4,0), and d(-2,-2). in two or more complete sentences, explain how you can use the coordinates of the vertices to prove that parallelogram abcd is a rectangle.

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Mathematics, 24.06.2019 03:30, owo73

Diagonals ac and bd form right angles at point m in parallelogram abcd. prove abcd is a rhombus. statements reasons 1. abcd is a parallelogram 1. given 2. ∠amb, ∠bmc, ∠cmd, and ∠dma are right angles 2. given 3. ∠amb ≅ ∠bmc ≅ ∠cmd ≅ ∠dma 3. right angles are congruent 4. ac bisects bd; bd bisects ac; 4. diagonals of a parallelogram bisect each other 5. am ≅ mc, mb ≅ md 5. definition of a bisector 6. ? 6. sas congruency theorem 7. ab ≅ bc ≅ cd ≅ da 7. cpctc 8. figure abcd is a rhombus 8. definition of a rhombus △abc ≅ △adc ≅ △bad ≅ △bcd △amb ≅ △cmb ≅ △cmd ≅ △amd △abc ≅ △adc ≅ △amd ≅ △bmc △amb ≅ △cmd ≅ △bad ≅ △bcd

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Mathematics, 30.06.2019 02:40, mom2acjm

Parallelogram abcd has vertices: a(-3,1), b(3, 3), c(4,0), and d(-2,-2). in two or more complete sentences, explain how you can use the coordinates of the vertices to prove that parallelogram abcd is a rectangle.

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Mathematics, 19.07.2019 12:00, claudiasfandom

Ihad the question: "four points a, b, c and d lie on the curve with equation y = x^2. prove that abcd is never a parallelogram." i have a proof but i don't really think it's strong enough: co-ordinates for points of the parallelogram from left to right: (x3, y2), (x1, y1), (x4, y2), (x2, y1) y1 = x1^2 y1 = x2^2 y2 = x3^2 y2 = x4^2 x1 > x3 x2 > x4 x1^2 = x2^2 x1 ± x2 x3^2 = x4^2 x3 ± x4 as they are all different points: x1 = -x2 and x3 = -x4 or -x1 = x2 and -x3 = x4 so: x1 > x3 and -x1 > -x3 but x1 > x3 is equivalent to -x1 < -x3 -x1 > -x3 and -x1 < -x3 can't both be true therefore: abcd will never be a parallelogram is that valid? or could i make it stronger?

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