Factor the following polynomial by grouping.

( correct and best explained answer gets brainliest. )

Since all four terms don't have a common factor we will group them in pairs with common factors.
6uv - 3v^3 + 4u - 2v^2
6uv + 4u - 3v^3 - 2v^2
Take out 2u from the first two terms and -v^2 from the last two terms. The goal is to have a common factor once we take out the GCF's.
2u( 3v + 2) - v^2(3v + 2)
Now we have two terms:
[2u(3v+2)] + [-v^2(3v+2)]
These two terms have a GCF of (3v + 2). Take that out:
(3v + 2)(2u - v^2)

6uv-3v^3+4u-2v^2
=3v (2u-v^2)+2 (2u-v^2)
=(3v+2)(2u-v^2)
option A)

(x^2 means x raised to the power of two)

HOPE IT HELPS☺☺