What can you say about the end behavior of the function f(x)=log10(5x-1)

The given function is
f(x) = log₁₀(5x-1)

As x -> -∞, the argument of the log function becomes a large negative number.
Because the log of a negative number is undefined, f(x) is undefined as x -> -∞.

As x -> +∞, the argument of the log function becomes a large positive number.
Therefore f(x) -> +∞ as x -> +∞.

As x -> -∞, f(x) is undefined.
As x-> +∞, f(x) -> +∞.

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2