If a couple plans to have 88 ? children, what is the probability that there will be at least one boyboy? ? assume boys and girls are equally likely. is that probability high enough for the couple to be very confident that they will get at least one boyboy in 88 ? children?

I'm assuming that the number of children the couple wanted is 8 and not 88.

Probability of having a boy or a girl is each 1/2 or 50%.

The couple wanted at least 1 boy. So the combination could be:

boy   girl
1       7
2       6
3       5
4       4
5       3
6       2
7       1
8       0

We can get probability of having at least 1 boy by deducting the probability of having no boys from 1.

Probability of at least 1 boy = 1 - Probability of having no boys.

P(at least 1 boy) = 1 - P(no boys or all girls)
P(at least 1 boy) = 1 - 0.50⁸
P(at least 1 boy) = 1 - 0.0039
P(at least 1 boy) = 0.9961

The probability of having at least 1 boy is 0.9961 or 99.61%. The probability is close to 1 and its high enough for the couple to be confident that they will have at least 1 boy in 8 children.