Asurvey about phone service has a margin of error of +/– 5%. out of 100 people surveyed, 93 said that they were with their service. the phone company has 80,000 customers. what is the range of the number of people that are satisfied? a. 70,680 to 78,120 customers b. 70,580 to 78,120 customers c. 70,680 to 78,210 customers d. 70,080 to 78,120 customers

Option A

Step-by-step explanation:

Given that a survey about phone service has a margin of error of +/– 5%

Out of 100 people surveyed, 93 said that they were pleased with their service.

Hence we can expect out of 80000 customers, 80000*93/100 customers would say they would be pleased with the service

i.e. 74400 would be average

The interval of range must have 74400 as mid value and on either side 5%

A) Mid point - 74400

This is the only range which has 74400 as mid value

So option A is right

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3