What is the vertex of the parabola given by the equation y x^2+ 4?

Format of Quadratic Equation:  y = ax2 + bx + c

Given Quadratic Equation:  y = 2x2 - 3x + 3

Coefficient Variable Values:  a = 2 and b = -3 and c = 3

Axis of Symmetry:  x = -b/2a = -(-3)/2(2) so answer is x = 3/4

Vertex:  x value is axis of symmetry (3/4) and y value is calculated substituting 3/4 for x in original equation:  y = 2(3/4)2 - 3(3/4) + 3 = 2(9/16) - 9/4 + 3 = 9/8 - 9/4 + 3 = 9/8 - 18/8 + 24/8 = 15/8,
so answer is (3/4,15/8)

x intercepts (solve using quadratic formula):  x = (-b plus or minus sqrt(b2 - 4ac)/2a, so plugging in coefficient values for a and b and c, we get x = [-(-3) plus or minus sqrt((-3)2 - 4(2)(-3)]/2(2), which results in x = (3 + sqrt(33))/4 or (3 - sqrt(33))/4 and answers to nearest tenth are x = (3 + 5.7) / 4 = 2.2
or x = (3 - 5.7) / 4 = -0.7

y intercept is calculated by substituting zero for x into original equation:  y = 2x2 - 3x + 3, so y-intercept is 3.

Domain is range is from calculated negative x intercept (-0.7) to calculated positive x intercept (2.2) and is written as (-0.7,2.2)

Range is from calculated y-intercept to positive infinity, since parabola opens up due to positive x2 coefficient value, so range is written as (3,positive infinity).  Note:  infinity symbol is sideways 8.         

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step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068