Gerald can complete a math assignment in 2 hours and a physics assignment in 1 hour. if he has 8 hours to complete a set of assignments, how many math assignments can he complete if he decides to leave the science assignments for the next day? this situation is given by 2x + y = 8, where x is the number of completed math assignments and y is the number of completed science assignments. (x 0, y 0, x and y take only integer values)

4  assignments of math

Step-by-step explanation:

Gerald can complete a math assignment in 2 hours

Gerald can complete a physics  assignment in 1 hours

Equation :

where x is the number of completed math assignments

y is the number of completed science assignments.

Since we are given that he decided to leave science assignment for the next day .

So, substitute y = 0

Hence he can complete 4 assignments of math if he decides to leave the science assignments for the next day.  

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

∡ eia and ∡ kij are congruent

step-by-step explanation: