There is a margin of error on a food survey of 6%. what is the range of the number of students who prefer chicken strips to meatloaf if 65 of 97 students said they prefer chicken strips and there are 1070 students at the school?

a.674 to 706 students
b.647 to 760 students
c.674 to 760 students
d.647 to 706 students

To answer this, we must recall that the range or the confidence interval is calculated as:

CI = X ± MOE

Where:

X = mean sample size

X can be calculated by:

X = (65/97)*1070

X = 717 students

Since MOE is given in percentage, we will use in the formula:

MOE = 717 * 0.06 = 43

For the range or CI:

CI = 717 ± 43

CI = 674, 760

Therefore 674 to 760 students prefer chicken strips over meatloaf. The answer is letter C.

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

i dont know

step-by-step explanation:

umm. i dont know