In △mno, m = 20, n = 14, and m∠m = 51°. how many distinct triangles can be formed given these measurements?

One obtuse scalene triangle

Step-by-step explanation:

Given that in a triangle MNO side m =20, side n =14 and angle m = 51

Angle N = sin inverse of (nsin M/m) =32.957 degrees

Angle O = 180-M-N =96.043 degrees

Side o = 25.592

There is one triangle only.

This is because angle N can have two values 32.957 or 147.043

But if m = 51 other angle cannot be 147.043 hence there is only one value for angle N.

When there is only one value for angle N, angle O also can have only one value

So no of triangles = 1

b i think

step-by-step explanation:

not really sure

i think the answer is seven, for if i'm being useless °ω°

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