Aresearcher wants to construct a 99% confidence interval for the proportion of elementary school students in seward county who receive free or reduced-price school lunches. what sample size is needed so that the confidence interval will have a margin of error of at most 0.07?

The sample size can be calculated using the formula:

n = p (1-p) (Zc / m)^2

where:

p = proportion of students who received lunches= 0.5

Zc = taken from standard tables at 99% CI = 2.575

m = margin of error =  0.07

Substituting known values:

n = 0.5 (1-0.5) (2.575/0.07)^2

n = 338.3

n = 339 samples

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere