The perimeter of a parallelogram is 180 cm. one side exceeds the other by 10 cm. what are the lengths of adjacent sides of the parallelogram?

Step 1

Let’s assume a and b are the sides of the parallelogram. The perimeter of the parallelogram = 2( a+ b)

Step 2

According to the question, one side of the parallelogram exceeds the other side by 10 cm.

Therefore, a = b + 10

Step 3

Since, the perimeter of the parallelogram = 180 cm

Therefore, 2 ( a + b ) = 180

= 2 (b + 10 + b) = 180

= (2b + 10) = 180/2

= 2b = 90 – 10

= b = 80 /2

b = 40 cm

a = b + 10 = 40 + 10 = 50 cm

Hence, the sides of the parallelogram are 40 cm and 50 cm.

answer: add the !

step-by-step explanation: then we will answer

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.