What additional information could be used to prove that δxyz ≅ δfeg using asa or aas? check all that apply.
∠z ≅ ∠g and xz ≅ fg
∠z ≅ ∠g and ∠y ≅ ∠e
xz ≅ fg and zy ≅ ge
xy ≅ ef and zy ≅ fg
∠z ≅ ∠g and xy ≅ fe

∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE  are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.

Step-by-step explanation:

Given: ΔXYZ and ΔEFG such that ∠X=∠F

To prove they are congruent by using ASA or AAS conruency criteria

we need only one angle and side.

1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)

so we can apply ASA  such that ΔXYZ ≅ ΔFEG.

2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA  such that ΔXYZ ≅ ΔFEG.

3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA  such that ΔXYZ ≅ ΔFEG.

4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.

5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA  such that

ΔXYZ ≅ ΔFEG.

In Angle-Side-Angle (ASA or AAS) postulate one triangle is congruent to another triangle when two angles and included side of one triangle is congruent to two angles and included side of another triangle. Then, ΔXYZ ≅ ΔFEG when angle Z is congruent to angle G and side XZ is congruent to side FG.

Given :

According to the Angle-Side-Angle (ASA or AAS) postulate one triangle is congruent to another triangle when two angles and included side of one triangle is congruent to two angles and included side of another triangle.

So, according to the statement of ASA postulate the triangle XYZ is congruent to the triangle FEG when angle Z is congruent to angle G and side XZ is congruent to side FG.

For more information, refer the link given below:

link

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

idkidkdidkdkdidkx

step-by-step explanation:

nndncnd cnn

snddnd