The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. how long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? round to the nearest hundredth. the equation that represents the problem is 48 = 96t - 16t2. solve 16t2 - 96t + 48 = 0. complete the square to write 16t² - 96t + 48 = 0 as . solve (t - 3)² = 6. the arrow is at a height of 48 ft after approximately s and after s.

The arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

Explanation

The given formula is:  

If the initial velocity is 96 ft/s , that means  

For finding the time the arrow takes to reach a height of 48 ft, we will plug into the above formula. So......

So, the arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

or

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.