The number of rainbow smelt in lake michigan had an average rate of change of −19.76 per year between 1990 and 2000. the bloater fish population had an average rate of change of −92.57 per year during the same time. if the initial population of rainbow smelt was 227 and the initial population of bloater fish was 1,052, after how many years were the two populations equal?

For Edgenunity

The linear function that models the population of bloater fish is y2 =

-92.57 x + 1,052

The linear equation that determines when the two populations were equal is

-19.76 x + 227= -92.57x + 1052

The solution is x = 11.33 years

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: