Eric conducted a survey of the cars in four parking lots and wrote the following observations:
15 of the 36 cars in lot 1 were blue
43 of the 92 cars in lot 2 were blue
12 of the 30 cars in lot 3 were blue
32 of the 52 cars in lot 4 were blue
based on the survey, which parking lot had the greatest percentage of blue cars?

quick way the one with the 2 closest numbers

 other way divide all 4 options

15/36 = 0.41 = 41%

43/92 = 0.46 = 46%

12/30 = 0.4 = 40%

32/52 = 0.62 = 62% Lot 4 had highest percent

lot 4

Step-by-step explanation:

i took the test and got it right.  32/52 as a percentage is 61.538461538462% making it the highest percentage of them all.

yeet

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3