Atravel agency offers two dallas outings. plan a includes hotel accommodations for three nights and two pairs of texas rangers baseball tickets worth a total of $557. plan b includes hotel accommodations for five nights and four pairs of rangers baseball tickets worth $974. find the cost of one night’s hotel accommodations and the cost of one pair of baseball tickets.

We let x as the cost of one night’s hotel accommodations and y as the cost of one pair of baseball tickets. For plan A, we can generate the equation as 3x + 2y = $557 and for plan B; 6x + 4y = $1114

Using elimination, we can write the two as:

3x + 2y = 557

5x + 4y = 974

Multiply both eq. 1 by 2 to eliminate y

2(3x + 2y = 557)2

6x + 4y = 1114

We now have

6x + 4y = 1114

5x + 4y = 974        ⇒ subtract

X = 140

Substitute x to either equation to get the value of y

3(140) + 2y = 557

2y = 557 – 420

2y = 137

Y = 68.5

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

answer: (-6,3)

step-by-step explanation: