Show that p(x) = 2x^3 − 5x^2 − 10x + 5 has a real root.

All odd degrees polynomials with real coefficients have (at least) a real root, and are continuous.  This is because the curve goes diagonally and must pass through the x-axis.

The above polynomial can be evaluated at x1=-10 and x1=+10 (or any other large enough number)
f(-10)=-2395
f(10)=1405
Since they have opposite signs, the function must intersect the x-axis between x1 and x2 by the intermediate value theorem, hence there is (at least) one root.

It’s 24.6 after you round to the nearest tenths the answer should be 25.0

What are the choices