How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?

There are 10 digits from 0 to 9
When you say 4 digit number that means it can't start with zero, then
1) there are 9 ways to chose the 1st digit (excluding zero)
2) there are only 1 ways to chose the 2nd digit (only 8))
3) there are 10 ways to chose the 3rd digit
4) there are 10 ways to chose the 4th digit

TOTAL NUMBER OF WAYS: 9 x 1 x 10 x 10 = 900

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

The coefficient, 5 represents the length in relation to the problem.