What is the probability that, after making two rolls with a fair (six-sided) die, you find that one or both of the rolls is greater than or equal to 4?

There are 36 total possibilities when one rolls a six sided die. 
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6).
Out of these possibilities there are 3 that make 4.4 that make make 5. 5 that make 6. 6 that make 7. 5 that make 8. 4 that make 9. 3 that make 10. 2 that make 11 and 1 that makes 12. Now add the combinations 3+4+5+6+5+4+3+2+1. The answer would be 33. 

7.666270253x10 raised to the 18th power