Mathematics, 14.09.2020 05:01, kkbrookly7496

3x+2y+2z=3
x+2y-+z=5
2x-4y+z=0

Answers: 3

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Answers

3x + 2y + 2z = 3 ⇒ 3x + 2y + 2z = 3
1x + 2y - 1z = 5 ⇒ 1x + 2y - 1z = 5
2x - 4y + 1z = 0 4x + 4y + 1z = 8
   4x + 4y + 1z = 8 ⇒ 12x + 12y + 3z = 24
3x + 2y + 2z = 3    3x - 2y = 5 ⇒ 12x - 8y    = 20
1x + 2y - 1z = 5 ⇒ 1x + 2y - 1z = 5     20y + 3z = 4
2x - 4y + 1z = 0 ⇒ 2x - 4y + 1z = 0    20y - 20y + 3z = 4 - 20y
      3x - 2y = 5    3z = 4 - 20y
      3    3
      z = 1¹/₃ - 6²/₃y
         20y + 3(1¹/₃ - 6²/₃y) = 4
      20y + 4 - 20y = 4
      20y - 20y + 4 = 4
   0y + 4 = 4
       - 4 - 4
   0y = 0
      0    0
      y = 0
      20(0) + 3z = 4
      0 + 3z = 4
      3z = 4
   3 3
z = 1¹/₃
      4x + 4(0) + 1¹/₃ = 8
      4x + 0 + 1¹/₃ = 8
      4x + 1¹/₃ = 8
      - 1¹/₃ - 1¹/₃
    4x = 6²/₃      4    4
      x = 1²/₃

answered: Guest

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

answered: Guest

Hello!

the answer is:

$\frac{3^{4} }{3^{1}}=3^{3}$

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

$\frac{a^{m} }{a^{n} }=a^{m-n}$

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

$\frac{3^{4} }{3^{1}}$

then, calculating we have:

$\frac{3^{4} }{3^{1}}=3^{4-1}=3^{3}$

hence, the answer is:

$\frac{3^{4} }{3^{1}}=3^{3}$

have a nice day!

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3x+2y+2z=3
x+2y-+z=5
2x-4y+z=0...