Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. how many units below the y-intercept of g(x) is the y-intercept of f(x)?

The distance between y-intercepts of f(x) and g(x) = 3 units

Step-by-step explanation:

For better understanding of the solution, see the plotted graph which is attached below :

f(x) = x - 1

g(x) = x + 2

Now, to find the distance between the y - intercepts of f(x) and g(x), First find the y-intercepts of both the given functions

y-intercepts of f(x) = x - 1

At y-intercept the x-coordinate = 0

⇒ y = 0 - 1

⇒ y = -1

y-intercepts of g(x) = x + 2

At y-intercept the x-coordinate = 0

⇒ y = 0 + 2

⇒ y = 2

Now, distance between the two intercepts = 2 - (-1)

                                                                        = 2 + 1

                                                                        = 3

Hence, the distance between y-intercepts of f(x) and g(x) = 3 units

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: