![x=\frac{5}{6}](/tpl/images/0480/6917/54724.png)
![y=\frac{8}{5}](/tpl/images/0480/6917/05af1.png)
Step-by-step explanation:
![12x + 15=34](/tpl/images/0480/6917/57c61.png)
![-6x + 5y=3](/tpl/images/0480/6917/ef580.png)
In elimination method we try to make the coefficient of one variable same
LEts multiply the second equation by 2
* 2
![-12x + 10y =6](/tpl/images/0480/6917/b130d.png)
Now add it with first equation
![12x + 15y=34](/tpl/images/0480/6917/f92f9.png)
![-12x + 10y =6](/tpl/images/0480/6917/b130d.png)
-----------------------------------
![25y=40](/tpl/images/0480/6917/9df1c.png)
Divide by 25 on both sides
![y=\frac{8}{5}](/tpl/images/0480/6917/05af1.png)
Now plug it in first equation and find out x
![12x + 15y=34](/tpl/images/0480/6917/f92f9.png)
![12x + 15(\frac{8}{5})=34](/tpl/images/0480/6917/3d2c7.png)
, subtract 24
![12x =10](/tpl/images/0480/6917/96a77.png)
Divide by 12 on both sides
![x=\frac{5}{6}](/tpl/images/0480/6917/54724.png)