At which approximate x-value are these two equations equal
y = √1 - x^2
y = 2x - 1

Given the equations:

          ....[1]

                 .....[2]

Taking square both sides in [1]  we have;

              ....[3]

Substitute the equation [2] into [3] we have;

Using identity rule:

then;

Add both sides we have;

Subtract 1 from both sides we have;

⇒

By zero product property we have;

x = 0 and 5x-4 = 0

⇒x= 0 and

For x = 0,

y = 2(0)-1 = -1

Since, the value of x = 0 doesn't satisfy the equations.

Therefore, the values of x is 0.8

(3x-8) or (3x+8)

step-by-step explanation: