In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of a degree, determine the measure of the smallest angle in the triangle.

We can use the Сosine formula to solve this problem.
First we must find the third side (АС) of the triangle:



The smallest angle of the triangle lies opposite the smallest side, so we need to find m∠C.



Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

38.7°

I hope this helps

The final answer is 3x3+6x2+8x+24+47x−2mark me brainliest