Mathematics, 20.08.2019 08:00, reaperdraws
What is the derivative of y=ln(sec(x)+tan(x))y=ln(sec(x)+tan(
Answers: 1
![y = ln(sec(x)+tan(x)) \\ \\ y' = \frac{1}{sec(x)+tan(x)} * [tan(x)sec(x) + sec^2(x)] \\ \\ y' = \frac{sec(x)(sec(x) + tan(x))}{sec(x)+tan(x)} \\ \\ y' = sec(x) + C](/tpl/images/0181/1774/d1150.png)
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