Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers

4 consecutive odd integersx , x + 2, x + 4, x + 6

product of 2 smaller numbers is 64 less then the product of the 2 larger numbers

x(x + 2) = (x + 4)(x + 6) - 64
x^2 + 2x = (x^2 + 10x + 24 - 64)
x^2 + 2x = x^2 + 10x - 40
2x = 10x - 40
2x - 10x = -40
-8x = -40
x = -40/-8
x = 5

x + 2 = 5 + 2 = 7
x + 4 = 5 + 4 = 9
x + 6 = 5 + 6 = 11

ur numbers are : 5,7,9,and 11