The probability that a train leaves on time is .07. the probability that the train arrives on time and leaves on time is 0.56. what is the probability that the train arrives on time, given that it leaves on time?

Event A: leave on time  P(A) = 0.7
Event B: arrive on time  P(B) = ?
Both: P(A)*P(B) = 0.56  -> P(B) = 0.8

I'm assuming you are typing the number wrong for event A

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