Acountry's population in 1993 was 171 million. in 1999 it was 176 million. estimate the population in 2012 using the exponential growth formula. round your answer to the nearest million.

This is the concept of application of an exponential growth functions. This question can be modeled using the exponential formula;
f(t)=ae^(kt)
where;
a=initial population
f(x)=current population
t=time
k=constant of proportionality
suppose the time at 1993 is t=0 and time in 1999 is t= 6
N/B. The population is in millions;
Thus;
176=171e^(6t)
176/171=e^(6t)
introducing the natural logs we getL
6t=ln(176/171)
t=1/6ln(176/171)
t=0.0048
Hence;
f(t)=171e^(0.0048t)
Therefore the population in 2012 will be:
t=19
thus;
f(t)=171e^(0.0048*19)
f(t)=187.33
Thus, the population will be given by:
f(t)=187 million

Iplay an instrument and i'm in band