Write an equation if a line perpendicular to line ab below in slope intercept form that passes through the point 7,6

y=.5x+2.5

Step-by-step explanation:

To calculate this we first have to calculate the slope of the given line, remember that perpendicular lines have reciprocal slopes, that means that the slopes are flipped upside down and the product of its multiplication should be -1.

So the formula for slope is the next one:

Since the slope of the given line is -2 the reciprocal would be1/2, and we insert that into the formula for line:

y(-y1)=m(x-x1)

y-6=1/2(x-7)

y=1/2x-3.5+6

y=.5x+2.5

And that would be the answer.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

b

step-by-step explanation: