Two equations are given below: a – 3b = 22 a = b – 2 what is the solution to the set of equations in the form (a, b)? (–10, –8) (–12, –10) (–8, –6) (–14, –12)

Hi Kristian

a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
b - 2 - 3b = 22
-2b - 2 = 22
 -2b = 22 + 2
-2b = 24
b = 24/-2
b = -12

Now substitute -12 for b in a = b - 2
a = b -2
a= -12 - 2
a= -14

Thus, the solution is a = -14 and b = -12

The correct option is the last one (-14,-12)

If you have questions about my answer, please let me know.

Good luck!