Could i get some i give . and this is worth 18
what is the surface area of a cylinder with a radius of 3 in. and a height of
4 in.? use 3.14 for p. show the equation you use as well as all of your work to solve.
put each step of your work in a new line.

The formula for the surface area of a cylinder is A=2πrh+2πr².

A=2πrh+2πr²
  =2(3.14)(3)(4) + 2(3.14)(3)²
  =6.28*3*4 + 6.28*9
  =75.36+56.52
  =131.88
The surface area of the cylinder is 131.88 in.²

As for the triangular prism, the formula is SA = wh + lw + lh + ls
w=width (2.7)
h=height (1.1)
l=length (4.2)
s=side

Since you don't know the side (which is the hypotenuse of the right triangle, use the Pythagorea formula a² + b² = c²

2.7² + 1.1² = c²(side)
7.29+1.21=8.5
The side is 8.5cm.
Now plug w, h, l, and s into SA = wh + lw + lh + ls

SA= (2.7*1.1)+(4.2*2.7)+(4.2*1.1)+(4.2*8.5)
SA= 2.97+11.34+4.62+35.7
SA=54.63
The surface area of the triangular prism is 54.63cm².

I hope I helped

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm