Ascrewdriver

is dropped from the top of an elevator shaft
.
exactly 6.0

seconds later, the sound of the screwdriver

hitting bottom is heard. how deep is the shaft
?
(hint: the distance that a dropped object falls in t seconds is represented by the formula sequals
16tsquared
.
the speed of sound is 1100 ft/sec.)

495.92 m

Step-by-step explanation:

Let h be the height of the shaft

t = Time taken by the screwdriver to fall to the ground

Time taken to hear the sound is 6 seconds

Time taken by the sound to travel the height of the shaft = 6-t

Speed of sound in air = 1100 ft/s

For the stone falling

For the sound

Distance = Speed × Time

Here, distance traveled by the screwdriver and sound is equal

The time taken to fall down is 5.55 seconds

Height of the shaft is 495.92 m

my acc plz

step-by-step explanation:

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you