Aball is thrown into the air with an upward velocity of 48 ft/s. its height h in feet after t seconds is given by the function h=-16t^2+48t+6. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ball’s maximum height? a. 3 s; 6 ft b.1.5 s; 54 ft c. 1.5 s; 114 ft d. 1.5 s; 42 ft

time = -48/(2*-16) = 1.5 seconds

height = -16(1.5)^2+48(1.5)+6 = 42 ft

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.