Solve the triangle. round lengths to the nearest tenth and angle measures to the nearest degree. b = 15° c = 113° b = 49
a. a = 50°, a = 176.3, c = 151.2
b. a = 52°, a = 149.2, c = 174.3
c. a = 52°, a = 151.2, c = 176.3
d. a = 50°, a = 174.3, c = 149.2

So,Given that you have A = 23 degrees , B = 21 degrees ,
and side a = 42.8, we find the angle C and the remaining sides of the triangle to be as follows:

Calculating for C = 180 degrees - ( A + B ).
C = 180 - 44 = 136

a / sin A = b / sin B = c / sin C

b = a sin B/ sin A = 42.8 sin 21 / sin 23 = 39.3
c = a sin C/ sin A = 42.8 sin 136/ sin 23 = 76.1

42.8/sin 23 = 109.5
39.3/sin 21 = 109.7
76.1/sin 136 = 109.6

The correct answer is ( c ). C = 136, b = 39.3 , and c = 76.1.

Ais c multiple rthvjjbv