An observer (o) spots a plane (p) taking off from a local airport and flying at a 23° angle horizontal to her line of sight and located directly above a tower (t). the observer also notices a bird (b) circling directly above her. if the distance from the plane (p) to the tower (t) is 5,000 ft., how far is the bird (b) from the plane (p)? round to the nearest whole number.

Here, O represents the observer , P represents the Plane,  T represents the tower and B represents the Bird

As per the statement:

The observer also notices a bird (B) circling directly above her and the distance from the plane (P) to the tower (T) is 5,000 ft.

⇒Distance from the plane to the tower = 5000 ft.

Angle of elevation()= 23 degree.

We have to find how far is the bird (B) from the plane (P):

Using cosine ratio:

See the diagram as shown below:

Here, Base side = 5000 ft and Hypotenuse side = distance of bird from the plane

Substitute the given values we have;

or

Simplify:

ft

Therefore, 5432 ft far is the bird (B) from the plane (P)

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x