Juan analyzes the amount of radioactive material remaining in a medical waste container over time. he writes the function f(x) = 10(0.98)x to represent the amount of radioactive material that will remain after x hours in the container. rounded to the nearest tenth, how much radioactive material will remain after 10 hours?

since x  is the number of hours and they give you 10 hours replace 10 for x

 so it becomes 10 x (0.98) x 10 = 98

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: