Mathematics, 23.09.2019 20:30, annalaurie7
Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < Ο
Answers: 1
. Then
![\implies\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac{\mathrm d}{\mathrm dt}\left[\frac14\sec t\right]}{-4\sin t\cos t}=\dfrac{\frac14\sec t\tan t}{-4\sin t\cos t}=-\dfrac1{16}\sec^3t](/tpl/images/0255/9177/55c1a.png)
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Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < Ο...
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