Which is the axis of symmetry of a parabola with equation y^2=-8x?

x = -4

Step-by-step explanation:

Given the equation of the parabola y² = -8x, the axis of symmetry has equation to be x = c

To get the value of x from the equation, we will use the related

x = -b/2a

The equation given can be rewritten as y²+8x = 0

Comparing this with he general form of a quadratic equation

ax²+bx+c = 0

a = 1, b = 8

x = -8/2(1)

x = -8/2

x = -4

The axis of symmetry of the parabola is at x = -4.

Note that the axis of symmetry passes through the vertex of the parabola

i can

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐