Which solution to the equation 3/2g+8=g+2/g^2-16 is extraneous?
a g = –4
b g = –4 and g = 16
c neither g = –4 nor g = 16
d g = 16

A) g = –4

Step-by-step explanation:

The given equation is:

We cross multiply to get:

Expand to get:

Group similar term;

The domain of the given function is

Therefore g=-4 is an extraneous is an extraneous solution

answer: y=4000x+14000

step-by-step explanation:

so then what are you asking?

step-by-step explanation: