Write the expression for the function whose graph is the graph of y = x^3 but shifted down 4 units and left 5 units.

a.
y = (x - 5)^3 - 4

b.
y = (x + 5)^3 - 4

c.
y = (x - 5)^3 + 4

d.
y = (x - 4)^3 - 5

1. Consider y=f(x)

2. let a and b be 2 positive numbers

3. then the graph of y=f(x)-a is the graph of y=f(x) shifted a units down

4. the graph of y=f(x+b) is y=f(x) shifted b units left
                        y=f(x-b)  is y=f(x)  shifted b units right

5. y=f(x+b)-a is the graph of y=f(x) shifted a units down and b units left

6. So shifted 4 units down and 5 units left is the graph of 
              
       

7. To check: consider  at x=3. We have the point (3, 27)

     Shift this point 4 units down and 5 units left: (3-5, 27-4)=(-2, 23)

     Consider   for x=-2

    

The skating rink rented 872 pairs of skates during april and may.why? : if the skating rink rented three times the pair of skates in april during may, they rented 654 skates. 218 x 3 = 654then, if they want to know how many they rented during both april and may, then you just add 654 (may) and 218 (april) to give you 872 pairs of skates for both months.654 + 218 = 872hope this !