Which statements are true about the graph of the function f(x) = x2 – 8x + 5? check all that apply. the function in vertex form is f(x) = (x – 4)2 – 11. the vertex of the function is (–8, 5). the axis of symmetry is x = 5. the y-intercept of the function is (0, 5). the function crosses the x-axis twice.

The options that are correct regarding graph of f(x) is:

   The function in vertex form is    The y-intercept of the function is (0, 5).    The function crosses the x-axis twice.Step-by-step explanation:

The function f(x) is given by:

       

We know that if the equation of parabola is written in general form as:

             

Then the vertex of parabola is: (h,k)

Also, the x-coordinate of vertex is the equation of the axis of symmetry of parabola.

Hence, on converting the equation to general form we get:Hence, the vertex of parabola is at (4,-11)and the axis of symmetry of parabola is: x=4Also, the y-intercept is the point where x=0Hence, when x=0 we get: f(x)=5

              Hence, y-intercept is: (0,5)

Also, by the graph we see that the graph of the function crosses the x-axis twice ( at x=0.683 and at x=7.317 )

Its the first one: the function in vertex form is f(x)=(x-4)^2-11

Xis equal to three